1x^2-5x+8=0

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Solution for 1x^2-5x+8=0 equation:


Simplifying
1x2 + -5x + 8 = 0

Reorder the terms:
8 + -5x + 1x2 = 0

Solving
8 + -5x + 1x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-8' to each side of the equation.
8 + -5x + -8 + x2 = 0 + -8

Reorder the terms:
8 + -8 + -5x + x2 = 0 + -8

Combine like terms: 8 + -8 = 0
0 + -5x + x2 = 0 + -8
-5x + x2 = 0 + -8

Combine like terms: 0 + -8 = -8
-5x + x2 = -8

The x term is -5x.  Take half its coefficient (-2.5).
Square it (6.25) and add it to both sides.

Add '6.25' to each side of the equation.
-5x + 6.25 + x2 = -8 + 6.25

Reorder the terms:
6.25 + -5x + x2 = -8 + 6.25

Combine like terms: -8 + 6.25 = -1.75
6.25 + -5x + x2 = -1.75

Factor a perfect square on the left side:
(x + -2.5)(x + -2.5) = -1.75

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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